The sides of a rectangle are given by `x=pma` and `y=pmb`. The equation of the circle passing through the vertices of the rectangle is

Options

A. `x^(2)+y^(2)=a^(2)`
B. `x^(2)+y^(2)=a^(2)+b^(2)`
C. `x^(2)+y^(2)=a^(2)-b^(2)`
D. `(x-a)^(2)+(y-b)^(2)=a^(2)+b^(2)`

Answer

B

Explanation

Given sides of rectangle are
`x=pm a` and `y=pm b`
`:.` Centre of circle `=(0,0)`
and radius of circle `=sqrt(A^(2)+b^(2))``

` `:.` Equation of circle
`x^(2)+y^(2)=(a^(2)+b^(2))`