The potential energy function of a particle in the x-y plane is given by `U =k(x+y)`, where (k) is a constant. The work done by the conservative force in moving a particlae from (1,1) to (2,3) is .

The potential energy of a particle in the X-Y plane is given by U=k(x+y) , where 'k' is a constant. Find the amount of work done by the conservative force in moving a particle from (1, 1) to (2, 3).

The potential energy of a particle moving along x-axis is given by U = 20 + 5 sin (4 pi x) , where U is in J and x is in metre under the action of conservative force :

In a two dimensional space the potential energy function for a conservative force acting on a particle of mass m = 0.1 kg is given by U = 2 (x + y) joule (x and y are in m). The particle is being moved on a circular path at a constant speed of V = 1 ms ^(-1) . The equation of the circular path is x^2 + y^2 = 42 . (a) Find the net external force (other than the conservative force) that must be acting on the particle when the particle is at (0, 4). (b) Calculate the work done by the external force in moving the particle from (4, 0) to (0, 4).

The potential energy of a partical of mass 2 kg moving in y-z plane is given by U=(-3y+4z)J where y and z are in metre. The magnitude of force ( in newton ) on the particle is :

The potential energy of a particle of mass 5 kg moving in the x-y plane is given by U=(-7x+24y)J , where x and y are given in metre. If the particle starts from rest, from the origin, then the speed of the particle at t=2 s is

The potential energy of a particle of mass 5 kg moving in the x-y plane is given by U=(-7x+24y)J , where x and y are given in metre. If the particle starts from rest, from the origin, then the speed of the particle at t=2 s is

The potential energy of a particle of mass 5 kg moving in the x-y plane is given by U=(-7x+24y)J , where x and y are given in metre. If the particle starts from rest, from the origin, then the speed of the particle at t=2 s is

The potential energy of a certain particle is given by U = 30x^2 - 20 y^2 . Find the force acting on the particle.

The potential energy function for a particle executing linear SHM is given by V(x)= 1/2kx^2 where k is the force constant of the oscillator. For k = 0.5 Nm^(-1) , the graph of V(x) versus x is shown in the figure A particle of total energy E turns back when it reaches x=pmx_m .if V and K indicate the potential energy and kinetic energy respectively of the particle at x= +x_m ,then which of the following is correct?

The potential energy function for a particle executing linear SHM is given by V(x)= 1/2kx^2 where k is the force constant of the oscillator. For k = 0.5 Nm^(-1) , the graph of V(x) versus x is shown in the figure A particle of total energy E turns back when it reaches x=pmx_m .if V and K indicate the potential energy and kinetic energy respectively of the particle at x= +x_m ,then which of the following is correct?