How do the basicity and solubility in water vary from `Be(OH)_(2)` to `Ba(OH)_(2)` ?

Arrange the following compounds in the increasing order of solubility in water:(i) O Mg(OH)_2, Be(OH)_2, Ba(OH)_2, Ca(OH)_2, Sr(OH)_2 (ii) SrSO_4, MgSO_4, BeSO_4, BaSO_4o, CaSO_4 .

Why solubility of alkaline earth metal hydroxides increases from Be(OH)_(2) to Ba(OH)_(2) ?

Why solubility of alkaline earth metal hydroxides increases from Be(OH)_(2) to Ba(OH)_(2) ?

Arrange the following in decreasing order of solubility in Water. (i) Be(OH)_(2),Ca(OH)_(2),Ba(OH)_(2),Sr(OH)_(2) . (ii) BaSO_(4), MgSO_(4), CaSO_(4), SrSO_(4) .

Arrange the following in decreasing order of solubility in water. Be(OH)_2,Ca(OH)_2,Ba(OH)_2,Sr(OH)_2

Normally and molarity: An aqueous solution contains 9.50g of barium hydroxide in 200 mL of solution. Calculate (i) the molartiy and (ii) the normally of the solution. Strategy : Convert grams of Ba(OH)_(2) to moles of Ba(OH)_(2) and then calculate molarity. Becuase each formula unit of Ba(OH)_(2) furnishes two Oh ions, 1 mol Ba (OH)_(2) = 2 eq Ba(OH)_(2) . Thus, normally is twice of molarity for Ba (OH)_(2) solution.

Ba(OH)_2 + Cl_2 to