Prove : nPr = n (n-1)P(r-1)...

Prove : ` nPr = n (n-1)P(r-1)`

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`.^nP_r=.^nC_r*r!`
`=(n!)/((n-r)!*r!)*r!`
`=(n!)/(n-r)!`.
`=n (n-1)!*(r-1)!`
`=n*(n-1)C_(r-1)*(r-1)!`
`n*(n-1)P_(r-1)`

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