" The de-Broglie wavelength "lambda

Two particles having de-Broglie wavelengths lambda_(1) and lambda_(2) , while moving along mutually perpendicular directions, undergo perfectly inelastic collision. The de-Broglie wavelength lambda , of the final particle is

A nucleus A, With a finite de-broglie wavelength lambda_(A) , undergoes spontaneous fission into two nuclei B and C of equal mass. B flies in the same direction as that of A, While C flies in the opposite direction with a velocity equal to half of that of B . The de-Broglie wavelength lambda_(B) and lambda_(B) and C are respectively:

A nucleus A, With a finite de-broglie wavelength lambda_(A) , undergoes spontaneous fission into two nuclei B and C of equal mass. B flies in the same direction as that of A, While C flies in the opposite direction with a velocity equal to half of that of B . The de-Broglie wavelength lambda_(B) and lambda_(B) and C are respectively:

de-Broglie wavelength lambda is

A proton and an electron are accelerated by same potential difference have de-Broglie wavelength lambda_(p) and lambda_(e ) .

A proton and an alpha -particle are accelerated, using the same potential difference. How are the de-Broglie wavelengths lambda_(p) and lambda_(a) related to each other?

A proton and an alpha =particle are accelerated using the same potential difference.How are the de-Broglie wavelengths lambda_(p) and lambda_(a) related to each other?

A proton and an alpha -particle are accelerated, using the same potential difference. How are the de-Broglie wavelengths lambda_(p) and lambda_(a) related to each other?

A proton and an alpha-particle are accelerated using the same potential difference. How are the de-Broglie wavelengths lambda_p and lambda_alpha related to each other?

Electrons with de-Broglie wavelength lambda fall on the target in an X-ray tube. The cut-off wavelength of the emitted X-ray is