di Vi= 2=3 and Vi=2 TE O resistance Risotto freeonel cueres. These re mieres fire are then cometen maa resultant resistance of this combination bere then the ratio - RS a 125 15 5 25

Two cells one of emf 1.4 V and internal resistance 0.6 Omega the other of emf 2.5. V and internal resistance 0.3 Omega are connected in parallel and the combination is connected in series with an external resistance of 4 Omega . What is the current through this resistance?

How will you connect three resistors of 2Omega, 3Omega and 5Omega respectively so as to obtain a resultant resistance of 2.5 Omega ? Draw the diagram to show the arrangement.

(a) What is the ratio of potential difference and current known as? (b) The values of potential difference V applied across a resistor and the corresponding values of current I flowing in the resistor are given below: {:("Potential difference"V("in volts"),:,2.5,5.0,10.0,15.0,20.0,25.0),("Current,I"("in amperes"),:,0.1,0.2,0.4,0.6,0.8,1.0):} Plot a graph between V and I, and calculate the resistance of the resistor. (c) Name the law which is illustrated by the above V-I graph. (d) Write down the formula which states the relations between potential difference, current and resistance. (d) The potential difference between the terminals of an electric iron is 240V and the current is 5.0A. What is the resistance of the electric iron?

The resistance of decinormal solution is found to be 2.5 xx 10^(3) Omega . The equivalent conductance of the solution is (cell constant = 1.25 cm^(–1) )