For parabola `y = 3x^2 - 12x - 2`, find the axis of symmetry x = ?

Find the equation of normal to the parabola y^(2)=12x at (3t^(2),6t) . Hence, find the equation of the normal to this parabola which makes an angle 135^(@) with the x-axis.

Consider the parabola y^2=12x Find the coordinate of the focus.

The area bounded by the parabola 4y=3x^(2) , the line 2y=3x+12 and the y - axis is

Find the area enclosed by the parabola 4y = 3x^(2) and the line 2y = 3x + 12.