Two planets of masses `M` and `M/2` have radii `R` and `R/2` respectively. If ratio of escape velocities from their surfaces `(v_1)/(v_2)` is `n/4` , then find n :

The escape velocity of a satellite from the surface of a planet is sqrt(2) times the orbital velocity of the satellite. If the ratio of the masses of two given planets is 1 : 4 and that of their radii is 1 : 2, respectively, then find the ratio of escape velocities of a satellite from the surfaces of two planets.

The ratio of the masses and radii of two planets are 2:3 and 8:27.The ratio of respective escape speeds from their surfaces are

The ratio of the masses and radii of two planets are 2 : 3 and 4 : 9. What is the ratio of the escape speed at their surface ?

The ratio of the masses and radii of two planets are 2 : 3 and 4 : 9. What is the ratio of the escape speed at their surface ?

The ratio of the masses and radii of two planets are 2 : 3 and 4 : 9. What is the ratio of the escape speed at their surface ?

Two particles having masses M and m are moving in a circular path having radii R and r respectively. If their periods are same, then the ratio of their angular velocities will be

Planet A has massa M and radius R. Planet B has half the mass and half the radius of Planet A.If the escape velocities from the Planets A and B are v_(A) and v_(B), respectively , then (v_(A))/(v_(B))=n/4. The vlaue of n is :