" In a "/_ABC" if "a=6,b=3" and "cos(A-B)=(4)/(5)" then area of triangle is equal to "

In Delta ABC , a= 6 ,b=3 and cos (A-B) = 4/5 .Then are of triangle is

If in a /_ABC,a=6,b=3 and cos(A-B)=(4)/(5) then find its area.

In Delta ABC, if a = 6, b=3 and cos (A-B) = (4)/(5) " then " angle C =

If in a triangle ABC,a=6,b=3 and cos(A-B)=(4)/(5) find the area of the triangle.

In a triangle ABC, two sides are a = 6, b = 3 and cos(A-B) =(4)/(5) then the area of the triangle is

If in Delta ABC,a=5,b=4 and cos(A-B)=(31)/(32) ,then

Let a,b, c are the sides opposite to angles A, B , C respectively in a Delta ABC tan""(A-B)/(2)=(a-b)/(a+b)cot ""C/2 and (a)/(sin A)=(b)/(sin B) =(c)/(sin C), If a=6,b=3 and cos (A-B) =4/5 Area of the trianlge is equal to

Let a,b, c are the sides opposite to angles A, B , C respectively in a Delta ABC tan""(A-B)/(2)=(a-b)/(a+b)cot ""C/2 and (a)/(sin A)=(b)/(sin B) =(c)/(sin C), If a=6,b=3 and cos (A-B) =4/5 Area of the trianlge is equal to

Let a,b, c are the sides opposite to angles A, B , C respectively in a Delta ABC tan""(A-B)/(2)=(a-b)/(a+b)cot ""C/2 and (a)/(sin A)=(b)/(sin B) =(c)/(sin C), If a=6,b=3 and cos (A-B) =4/5 Area of the trianlge is equal to

Let a = 6, b = 3 and cos (A -B) = (4)/(5) Area (in sq. units) of the triangle is equal to