Provethat the average of the numbers `n sin n^@`, n = 2,4,6...180 is `cot 1^@`

Prove that the average of the numbers n sin n^@ , n = 2,4,6...180 is cot 1^@

Prove that the average of the numbers n sin n^@ , n = 2,4,6...180 is cot 1^@

Provethat the average of the numbers n sin n^(@),n=2,4,6...180 is cot1^(@)

The arithmetic mean of the numbers 2s in2^0,4sin4^0,6sin^0, ddot, 178s in 178^0,180sin180^0 is sin1^0 b. "tan"1^0 c. cot1^0 d. t a n 89^0

If the average of m numbers is n^(2) and that of n numbers is m^(2) ,then the average of (m+n) numbers is m-n (b) mn(c)m+n (d) (m)/(n)

The average of numbers N1 and N2 is 17. The average of numbers N2 and N3 is 44. What is the difference between N3 and N1?