If `alpha, beta` are complementary angles and `sinalpha =3/5` ,then `sin alpha cos beta-cos alpha sin beta =`

If alpha,beta are complementary angles and sin alpha = (3)/(5) , then sin alpha cos beta - cos alpha sin beta =

If alpha , beta are complementary angles , sin alpha = 3//5 , then sin alpha cos beta - cos alpha sin beta =

If alpha, beta are complementary angles, sin alpha = (3)/(5) then cos alpha cos beta-sin alpha sin beta =

If alpha,beta are complementary angles, sin alpha=(4)/(5), then sin alpha cos beta+cos alpha sin beta=

If alpha , beta are complementary angles , then sin^(2) alpha + sin^(2) beta =

If alpha , beta are complementry angles such that bsin alpha = a , the find the value of (sin alpha cos beta - cos alpha sin beta) .

If alpha and beta are complementary angles, then show that cot beta+cos beta= (cos beta)/(cos alpha) (1+sin beta) .

(i) sin (alpha + beta) = sin alpha cos beta + cos alpha sin beta) (ii) sin (alpha-beta)= sin alpha cos beta- cos alpha sin beta Proof

If sin alpha=(12)/(13), cos beta =4/5 and alpha, beta are two acute angles, then Value of sin alpha cos beta +cos alpha sin beta is