If `theta` lies in the first quadrant and `5tan theta =4`, then `(5 sin theta - 3 cos theta)/(sin theta + 2 cos theta)=`

If theta lies in the first quadrant and 5 tan theta = 4 , " then " (5 sin theta - 3 cos theta )/( sin theta + 2 cos theta )=

If theta lies in the first quadrant and 5 tan theta = 4 , " then " (5 sin theta - 3 cos theta )/( sin theta + 2 cos theta )=

If theta lies in the first quadrant and 5 tan theta = 4 , " then " (5 sin theta - 3 cos theta )/( sin theta + 2 cos theta )= .............. A) 0 B) 1 C) 1/6 D) 5/14

If theta in the first quadrant and 5 tan theta =4 " then " ( 5 sin theta - 3 sin theta)/( sin theta + 2 cos theta) is equal to

If 3 cot theta = 5, then (5 sin theta - 3 cos theta)/(5 sin theta + 3 cos theta)

If 5tan theta=4 then value of ((5sin theta-3cos theta)/(5sin theta+3cos theta))=

If 5 tan theta =4 , then frac(5sin theta - 3cos theta )(5 sin theta + 2cos theta ) is equal to