[" If "aquad log_(10){98+sqrt(x^(2)-12x+36)}=2" ,The "x" effere "(y)/(6)],[[" (a) "4," (b) "8],[" (c) "12," (d) "4,8]]

If "log"_(10){98 + sqrt(x^(2) -12x + 36)}=2 , then x =

If "log"_(10){98 + sqrt(x^(2) -12x + 36)}=2 , then x =

If log_(10) (x^(2) - 12x + 36) = 2 , find x

IF log_(6)log_(2)[sqrt(4x+2)]+2sqrt(x)=0, then x=

Show that Lim_(x to 2) log_(10){x^(6) +sqrt((x^(2)+1292))}=2

the value of x, satisfying the equation log_(10)(98+sqrt(x^(3)-x^(2)-12x+36))=2 is

If log_(10 ) x - log_(10) sqrt(x) = (2)/(log_(10 x)) . The value of x is

If log_(10) sin x+log_(10)cos x=-1 and log_(10)(sinx+cosx)=(log_(10)n-1)/2 then the value of n is (a) 24 (b) 36 (c) 20 (d) 12_

The domain of y=log_(10)(sqrt(6-x)+sqrt(x-4)) is :