" In a triangle "ABC" ,if "(cos A)/(a)=(cos B)/(b)=(cos C)/(c)" and the stad "AB" at "D,E,F

In a triangle ABC if (cos A)/a=(cos B)/b= (cos C)/c , then Delta ABC is

In a triangle ABC,if (cos A)/(a)=(cos B)/(b)=(cos C)/(c) and the side a=2 then area of triangle is and the side a=2

In a triangle ABC, if (cos A)/(a) =(cos B)/(b ) =(cos C)/(c) and the side a=2, then the area of the triangle is-

In a Delta ABC(cos C+cos A)/(c+a)+(cos B)/(b) is

In a triangle ABC, cos A+cos B+cos C=

In a triangle ABC, cos A+cos B+cos C=

If in a Delta ABC,(cos A)/(a)=(cos B)/(b)=(cos C)/(c), then find the measures of angles A,B,C.

in a triangle ABC , ( cos A)/(a) = (cos B )/( b) = ( cos C )/( c ) if a=(1 )/( sqrt(6)) then the area of the triangle ( in square units ) is