[3x-2y+3z=8],[2x+y-z=1],[4x+3y+2z=4]

Find the solution of given system of equations: 3x+4y+5z=38, 2x-y+8z=33, 4x+3y+2z=25

x+2y-2z=5,3x-y+z=8,x+y-z=4

Solve : x-2y+3z=2 3x+y-z=3 8x-2y+4z=10

2x+3y+3z=5 x-2y+z=-4 3x-y-2z=3

Using matrices, solve the following system of equations for x,y and z: 2x+3y + 3z=5, x-2y + z = -4, 3x-y - 2z=3

2x-y+z=6,x+2y+3z=3,3x+y-z=4

2x+3y+z=17,x-y+z=3,3x+2y-2z=4

For the equations x+2y+3z=1, 2x+y+3z=2, 5x+5y+9z=4

2x-3y+5z=16, 3x+ 2y-4z= -4, x + y - 2z =- 3.