[" The magnitude of two vectors "vec P" and "vec Q" differ "],[" by "1." The magnitude of their resultant makes "],[" an angle of "tan^(-1)((3)/(4))" with "vec P" .The angle be- "]

The magnitudes of two vectors vecP and vecQ differ by 1. The magnitude of their resultant makes an angle of tan^(-1)(3//4) with P. The angle between P and Q is

The magnitudes of two vectors vecP and vecQ differ by 1. The magnitude of their resultant makes an angle of tan^(-1)(3//4) with P. The angle between P and Q is

The maximum value of the magnitude of the resultant of two vectors vec P and vec Q is 24 units and the minimum value of the magnitude of their resultant is 4 units. What is the ratio of the magnitudes of the vectors vec P and vec Q ?

The magnitude of the resultant vec R of two forces vec P and vec Q" is 20 N. "vec R make an angle of 30^(@) with vec P and an angle of 60^(@) with vec Q . What are the magnitudes of vec P and vec Q ?

The maximum magnitude of the resultant of two vectors, vec(P) and vec(Q) ("where" Pgt Q) is x times the minimum magnitude ot the resultant. When the angle between vec(P) and vec(Q)" ""is" " "theta , the magnitude of the resultant is equal to half the sum of the magnitudes of the two vectors. Prove that, cos theta =(x^2+2)/(2(1-x^2))*