Find the integral `int_0^6 e^(-st) t dt`

Let function F be defined as f(x)= int_1^x e^t/t dt x > 0 then the value of the integral int_1^1 e^t/(t+a) dt where a > 0 is

Obtain the following integrals : int6^(t)dt

Let function F be defined as f(x)=int_(1)^(x)(e^(t))/(t)dtx>0 then the vaiue of the integral int_(1)^(1)(e^(t))/(t+a)dt where a>0 is

Ifint_0^1(e^t dt)/(t+1)=a ,then find the value of int_(b-1)^b(e^(-t)dt)/(t-b-1)

If A = int_(0)^(1) (e^(t))/(1+ t)dt then int_(0)^(1) e^(t) ln (1 + t) dt=

If f(x)=x+int_0^1 t(x+t) f(t)dt, then find the value of the definite integral int_0^1 f(x)dx.

If f(x)=x+int_0^1 t(x+t) f(t)dt, then find the value of the definite integral int_0^1 f(x)dx.

If f(x)=x+int_0^1 t(x+t) f(t)dt, then find the value of the definite integral int_0^1 f(x)dx.

Find the value of definite integral: int_(0)^(pi) ((pit)/(2)-(t^(2))/(2))dt

int e^t sint dt