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Two concentric circle of radii 3 cm and 5 cm are given. Then length of chord BC which touches the inner circle at P is equal to

Text Solution

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From the given figure,
`OC = OA =5 cm`
`OP = OQ = 3cm`
Now, `OC^2= OP^2+CP^2`
`=>5^2 = 4^2+CP^2`
`=>CP^2 = 25-9 =16`
`=>CP = 4cm`
Now, `P` is the midpoint of `BC.`
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