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`sec sqrt(x)`

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Given, `y=sec sqrt(x)`
On differentiating w.r.t. x,
`(dy)/(dx)=(d)/(dx) (sec sqrt(x))`
`=sec sqrt(x)* tan sqrt(x)* (d)/(dx)(sqrt(x))`
`(dy)/(dx)=sec sqrt(x)* tan sqrt(x) * (1)/(2sqrt(x))`
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GURUKUL PUBLICATION - MAHARASHTRA PREVIOUS YEAR PAPERS- JULY 2016-Section-II
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