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If `bar(a),bar(b),bar(c)` are the position vectors of the points A,B,C respectively such that `3bar(a)+5bar(b)=8bar(c)`, the ratio in which A divides BC is

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Given `3bara + 5barb - 8barc = 0`
`3bara = 8barc - 5barc`
`bara= (8barc - bar5)/(3)`
`= (8barc - 5barc)/(8-5)`
By section formula , point A divides line segment BC extrnally in the ratio 8:5
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