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Evaluate : int(1)/(sinx.cos^(2)x)dx...

Evaluate : `int(1)/(sinx.cos^(2)x)dx`

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Let `I=int(1)/(sinx.cos^(2)x).dx`
`=int(sin^(2)x+cos^(2)x)/(sinx.cos^(2)x)dx`
`[:'sin^(2)x+cos^(2)x=1]`
`=int(sin^(2)x)/(sinx.cos^(2)x).dx+int(cos^(2)x)/(sinx.cos^(2)x).dx`
`=int(sinx)/(cosx).(1)/(cosx).dx+int(1)/(sinx).dx`
`=inttanx.secxdx+intcosecxdx`
:.I=secx+log|tan""(x)/(2)|+C`
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