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The general solution of the trigonometri...

The general solution of the trigonometric equation `tan^2theta=1` is

A

`theta=n pi pm(pi)/(3), n in z`

B

`theta = npi pm(pi)/(6), n in z`

C

`theta=n pi pm (pi)/(4), n in z`

D

`theta = n pi, n in z`

Text Solution

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The correct Answer is:
C
`tan^(2)theta = tan alpha`
`theta= n pi pm alpha`
`tan^(2)theta=1`
`tan^(2) theta=tan^(2).(pi)/(4)`
`therefore" "theta=n pi pm(pi)/(4)`
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GURUKUL PUBLICATION - MAHARASHTRA PREVIOUS YEAR PAPERS- MARCH 2014-SECTION-II
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