A solid cylinder of uniform density of radius 2 cm has mass of 50 g. If its length is 12 cm, calculate its moment of inertia about an axis passing through its centre and perpendicular to its length.

Explanation

To calculate the moment of inertia of a solid cylinder about an axis passing through its center and perpendicular to its length, we can use the formula:

\[ I = \frac{1}{4} m r^2 + \frac{1}{12} m l^2 \]

where:
- \( I \) is the moment of inertia,
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