A copper metal cube has each side of length 1 m. The bottom edge of the cube is fixed and tangential force `4.2xx10^(8)` N is applied to a top surface. Calculate the lateral displacemet of the top surface if modulus of rigidity of copper is `14xx10^(10)" N"//"m"^(2)`.

Explanation

Given : Length, `l=h=1" m",F=4.2xx10^(8)"N",eta=14xx10^(10)" N"//"m"^(2)`
Now, `" "eta=(Fh)/(Ax)=(Fh)/(lxxhxxx)`
`implies" "14xx10^(10)=(4.2xx10^(8)xx1)/(1xx1xxx)`
`implies" "x=(4.2xx10^(8))/(14xx10^(10))`
`=0.003" m"=3xx10^(-3)" m"`