Calculate the radius of second Bohr orbit in hydrogen atom from the given data.
Mass of electron `=9.1xx10^(-31)" kg"`
Charge on the electron `=1.6xx10^(-19)C`
Planck's constant `=6.63xx10^(-34)" J-s".`
Permittivity of free space `=8.85xx10^(-12)"C"^(2)//"Nm"^(2)`.

Explanation

We know that, `" "r_(n)=(n^(2)h^(2)epsilon_(0))/(pimZe^(2))`
For hydrogen Z = 1
`:." "r_(n)=(n^(2)h^(2)epsilon_(0))/(pime^(2))`
Radius of second Bhor orbit,
`r_(2)=(2^(2)xx(6.63xx10^(-34))xx8.85xx10^(-12))/(3.14xx9.1xx10^(-31)xx(1.6xx10^(-19))^(2))`
`implies" "=(1556.07xx10^(-80))/(73.15xx10^(-69))`
`implies" "~~21.3xx10^(-11)"m"`