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A particle rotates in U.C.M with ten...

A particle rotates in U.C.M with tengential velocity 'v' along a ghorizontal circle of diameter 'D' . Total angular displacement of the particle in time 't' is

A

`vt`

B

`(v/D)-1`

C

`(vt)/(2D)`

D

`(2vt)/(D)`

Text Solution

Verified by Experts

The correct Answer is:
D
`(2vt)/(D)`
Let, velocity be v an diameter be D.
`:. ` Radius `= D/2`
`omega = theta/t`
and `v = rxxomega`
`:. V = (D)/(2) xx (theta)/(t)`
`:. theta = (2vt)/(D)`
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