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Electric field intensity due to a charg...

Electric field intensity due to a charged sphere at a point outside the sphere decreases with `"……………….."`.

A

increase in charge on sphere

B

increase in dielectric constant.

C

decrease in the distance of from the centre of sphere.

D

decrease in the square of distance from the centre of sphere.

Text Solution

Verified by Experts

The correct Answer is:
b

Increase in dielectric constant
Electric field intensity at a point outside a charged conducting sphere is given as
`E = 1/(4piepsi).(q)/(r^(2))`
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