A uniform solid sphere has radius 0.2 m and density `8xx10^(3)kg//m^(2)`. Fing the moment of inertia about the tangent to its surface. `(pi=3.142)`

Explanation

We have, redius (R) =0.2 m and density `(p)=8xx10^(3)kg//m^(2)`
Moment of inertia about the tangent to its surface,
`I=I_(C)+MR^(2)`
[ using parallel axis theorem]
`(2)/(5)MR^(2)+MR^(2)`
`=(7)/(5)MR^(2)" "......(i)`
But, Mass (M) =Volume (V)`xx` Density (p)
`M=V_(p)=((4)/(3)piR^(3))p`
Putting the value of M ing (i), we get
`I=(7)/(5)((4)/(3)piR^(3))pR^(2)`
`=(28)/(15)piR^(5)p`
`=(28)/(15)xx3.142xx(2xx10^(-1))^(5)xx8000`