The energy of an excited hydrogen atom is `-0.85 eV`. Find the angular momentum of the electron.
`(h = 6.63 xx 10^(-34) J.s., pi = 3.142, E_(1) = -13.6 eV)`

Explanation

To find the angular momentum of the electron in an excited hydrogen atom with an energy of -0.85 eV, we can follow these steps:

### Step 1: Relate the energy to the principal quantum number (n)
The energy of an electron in the nth energy level of a hydrogen atom is given by the formula:
\[ E_n = -\frac{13.6 \, \text{eV}}{n^2} \]
Given that the energy \(E\) is -0.85 eV, we can set up the equation:
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