A particale in S.H.M. has a perod of 2 seconds and amplitude of 10 cm. Calculate the acceleration when it is at 4 cm from its positive extreme position.

Explanation

Given : A = 10 cm, T = 2 sec. ltbngt Acceleration, `a=omega^2((2pi)/T)^2x,`
`=(2xx22/7xx1/2)"^2,x`
Practicle is 4 cm from its positive exterme position.
`x=A-4`
`=10-4=6cm `
`a=(2xx22/7xx1/2)^2*0.06`
`a=(22xx22)/(49)xx0.06`
`a=0.5929`m//s^2`