A solid sphere of mass 1 kg rolls on a table with linear speed 2 m/s, find its total kinetic energy.

Explanation

Given : Mass of solid sphere (m) = 1 kg,
Linear speed (v) = 2 m/s.
Radius of gyration (k) for solid sphere
`=sqrt((2)/(5))R`
`therefore` Total kinetic energy, `E=(1)/(2) mv^(2)[1+(k^(2))/(R^(2))]`
`=(1)/(2)xx1xx2xx2[1+(2//5R^(2))/(R^(2))]`
`=2(1+(2)/(5))`
`=2xx(7)/(5)=(14)/(5)`
`=2.8J. `