An electron in an atom revolves around the nucleus in an orbit of radius 0.53 Å. If the frequency of revoluation of an electron is `9xx10^(9)` MHz. calculate the orbital angular momentum.
[Given : Charge on an electron `=1.6xx10^(-19)C`, Gyromagnetic ratio `8.8xx10^(10)C//kg, pi =3.142`]

Explanation

To calculate the orbital angular momentum of the electron revolving around the nucleus, we will follow these steps:

### Step 1: Understand the given data
- Radius of the orbit, \( r = 0.53 \, \text{Å} = 0.53 \times 10^{-10} \, \text{m} \)
- Frequency of revolution, \( f = 9 \times 10^{9} \, \text{MHz} = 9 \times 10^{15} \, \text{Hz} \) (since \( 1 \, \text{MHz} = 10^{6} \, \text{Hz} \))
- Charge of the electron, \( e = 1.6 \times 10^{-19} \, \text{C} \)
- Gyromagnetic ratio, \( \gamma = 8.8 \times 10^{10} \, \text{C/kg} \)
- Value of \( \pi = 3.142 \)
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