The periodic time of a linear harmonic oscillator is `2pi` second, with maximum displacement of `1cm`. If the particle starts from extreme position, find the displacement of the particle after `(pi)/(3)` seconds.

Explanation

Given: `T=2pi` second
`a=1cm`
`t=(pi)/(3)` second
`x=?`
`x=acos omegat`
`=1xxcos(2pi)/(2pi)xx(pi)/(3)` `[:'omega=2pif=(2pi)/(T)]`
`=cospi//3=0.5cm`.