Determine the binding energy of satellite of mass `1000 kg` revolving in a circular orbit around the Earth when it is close to the surface of Earth. Hence find kinetic energy and potential energy of the satellite.
[Mass of Earth `=6xx10^(24)kg`, radius of Earth `=6400km`, gravitational constant `G=6.67xx10^(-11)Nm^(2)//kg^(2)`]

Explanation

Given:
Mass of satellite, `m=1000kg`
Mass of earth, `M_(e)=6xx10^(24)kg`
Radius of earth, `R_(e)=6400km`
`=6.4xx10^(6)` metre
Gravitational constant, `G=6.67xx10^(-11)Nm^(2)//kg^(2)`
Binding energy of satellite`=?`
Kinetic energy and potential energy of satellite `=?`
Binding energy of satellite close to the surface of earth is given by
Binding energy `=+-(1)/(2)*(GM_(e)m)/(R_(e))`
`=(1)/(2)xx(6.67xx10^(-11)xx6xx10^(24)xx1000)/(6.4xx10^(6))`
`=3.1265xx10^(10)J`
Kinetic energy, `K.E.=(1)/(2)*(GM_(e)m)/(R_(e))`
`K.E.=3.1265xx10^(10)J`
Potential energy, `P.E.=-(GM_(e)m)/(R_(e))`
`:.P.E.=-2K.E.`
`P.E.=-6.2530xx10^(10)J`