Silver crystallises in FCC structure. If density of silver is 10.51g. `cm^(-3)`. Calculate the volume of unit cell. [Atomic mass of silver (Ag) `= 108 g m^(-1)`]

Explanation

Mass of 1 atom of Ag `= ("Atomic mass of Ag")/(N_(A))`
`= (108)/(6.033 xx 10^(23)`
`= 17.03 xx 10^(-23))`
Mass of unit cell = Atoms in unit cells `xx` mass of 1 atom
`= 4 xx 1.17.03 xx 10^(-23)`
`= 71.71 xxs 10^(-23) g`
Volume of unit cell = `("Mass of unit cell")/("Density")`
`= (71.71 xx 10^(-23))/(10.51)`
`= 68.24 xx 10^(-24)`