The Conductivity of 0.02M Ag `NO_(3)` at `25^(@)C` is `2.428 xx 10^(-3) Omega^(-1) cm^(-1)`. What is its molar conductivity?

Explanation

Molar conductivity = Conductivity `xx (1000)/("molar concentration")`
`= 2.428 xx 10^(-3) xx (1000)/(0.02)`
`= 2.248 xx 10^(-3) xx 50000`
`= 1214 xx 10^(-3) ohm^(-1) cm^(2) mol^(1)`