The power in dioptre of an equi-convex lens with radii of curvature of 10cm and refractive index 1.6 is

Calculate the focal length of a convex lens whose radii of curvature of two surfaces is 10cm and 15cm respectively and its refractive index is 1.5.

The power of a biconvex lens is 10 dioptre and the radius of curvature of each surface is 10 cm. Then the refractive index of the material of the lens is

The power of a biconvex lens is 10 dioptre and the radius of curvature of each surface is 10 cm. Then the refractive index of the material of the lens is,

The power of a biconvex lens is 10 dioptre and the radius of curvature of each surface is 10 cm. Then the refractive index of the material of the lens is

The focal length of an equi-convex lens is greater than the radius of curvature of any of the surfaces. Then, the refractive index of the material of the lens is

The power of a biconvex lens is 10 dioptre and the radius of corvature of each surface is 10 cm . Then the refractive index of the material of the lens is

What is the refractive index of material of a plano-convex lens, if the radius of curvature of the convex surface is 10 cm and focal length of the lens is 30 cm ?