A particle moves with a velocity `6hat(i)-4hat(j)+3hat(k)m//s` under the influence of a constant force `vec(F)= 20hat(i)+15hat(j)-5hat(k)N`.
The instantaneous power applied to the particle is

A particle moves with a velocity (5 hat(i)+3 hat(j)+6 hat(k)) m//s under the influence of a constant force (5 hat(i)+5 hat(j)+10hat(k))N . The instantaneous power applied to the particle is

A particle moves with a velocity vec(v)=5hat(i)-3hat(j)+6hat(k) " "ms^(-1) under the influence of a constant force vec(f)= 10hat(i)+10hat(j)+20hat(k)N . The instantanteous power applied to the particle is

A particle has initial velocity vec(v)=3hat(i)+4hat(j) and a constant force vec(F)=4hat(i)-3hat(j) acts on the particle. The path of the particle is :

If vec(F ) = (60 hat(i) + 15 hat(j) - 3 hat(k)) N and vec(V) = (2 hat(i) - 4 hat(j) + 5 hat(k)) m/s, then instantaneous power is:

If vec(F ) = (60 hat(i) + 15 hat(j) - 3 hat(k)) N and vec(V) = (2 hat(i) - 4 hat(j) + 5 hat(k)) m/s, then instantaneous power is:

If vec(F) = (60 hat(i) + 15hat(j) - 3hat(k)) and vec(v) = (2hat(i) - 4hat(j) + 5hat(k))m//s , then instantaneous power is :

A particle moves form position vec(s_(1))=(3hat(i)+2hat(j)-6hat(k)) m to position of vec(s_(2))=(14hat(i)+13hat(j)-9hat(k)) m, under the action of a force vec(F)=(14hat(i)+13hat(j)-9hat(k)) N, The work done by the force is

A particle moves form position vec(s_(1))=(3hat(i)+2hat(j)-6hat(k)) m to position of vec(s_(2))=(14hat(i)+13hat(j)-9hat(k)) m, under the action of a force vec(F)=(14hat(i)+13hat(j)-9hat(k)) N, The work done by the force is

A force vec(F) = (2hat(i) - 3hat(j) +7hat(k)) N is applied on a particle which displaces it by vec(S) = (4hat(i)+5hat(j) +hat(k)) . Find the work done on the particle .