The position vector `vecr` and linear momentum `vecp` and `vecr=hati` and `vecp=4hatj` the angular momentum vector is perpendicular to

The position of a particle is given by vecr=(hati+2hatj-hatk) momentum vecp=(3hati+4hatj-2hatk) The angular momentum is perpendicular to

The position of a particle is given by vecr=(hati+2hatj-hatk) and momentum vecp=(3hati+4hatj-2hatk) . The angular momentum is perpendicular to the

The position of a particle is given by vecr=(hati+2hatj-hatk) and momentum vecp=(3hati+4hatj-2hatk) . The angular momentum is perpendicular to the

A unit mass has vecr=8hati-4hatj and vecv=8hati+4hatj What is its angular momentum ?

If for some particle its position vector and linear momentum are respectively be 2hati+hatj+hatk and 2hati-3hatj+hatk . Its angular momentum will be:

If for some particle its position vector and linear momentum are respectively be 2hati+hatj+hatk and 2hati-3hatj+hatk . Its angular momentum will be:

The radius vector is 2hati+hatj+hatk while linear momentum is 2hati+3hatj+hatk . Then the angular momentum is