`1` mole of ferric oxalate is oxidised by `x` mole of `MnO_(4)^(-)` in acidic medium, Hence value of `x` is:

10 moles of ferric oxalate is oxidised by x mole of MnO_(4)^(-) in acidic medium. The value of 'x' is :

Five moles of ferric oxalate are oxidise by how much mole of KMnO_(4) in acidic medium.

Five moles of ferric oxalate are oxidise by how much mole of KMnO_(4) in acidic medium.

1 mol of ferrous oxalate is oxidized by x mol of MnO_4^(-) and also 1 mol of ferrous oxalate is oxidized by y mol of MnO_4^(-) in acidic medium. The ratio (x/y) is :

The number of moles of ferrus oxalate oxidised by one mole of KMnO_(4) in acidic medium is:

The number of moles of oxalate ions oxidised by one mole of MnO_(4)^(-) ion in acidic medium is :

The number of mole of oxalate ions oxidised by one mole of MnO_(4)^(-) ion is:

The number of mole of oxalate ions oxidised by one mole of MnO_(4)^(-) is :