ax^(2)+by^(2)=1

Factorise : ax^(2)+(a^(2)+1)x+a

The value of int(ax^(2))/(x sqrt(c^(2)x^(2)-(ax^(2)+b)^(2)))(1)/(c)sin^(-1)(ax+(b)/(x))+k csin^(-1)(a+(b)/(x))+esin^(-1)((ax+(b)/(x))/(c))+k( d) none of these

If the linear factors of ax^(2)-(a^(2)+1)x +a are p and q, then p+q is equal to

If ax ^(2) + 2hxy + by ^(2) =1 then (hx + by) ^(3) y _(2) =

In the integral int(dx)/(2ax-x^(2))^(1//2)=ansin^(-1)((x)/(a)-1), the value of n should be ( by dimensions ):

Factorise a^(2)x^(2)+(ax^(2)+1)x+a

" The locus of the vertices of the family of parabolas " y=ax^(2)+2a^(2)x+1 " is " (a!=0) " a curve passing through the point "

(2ax)/(a^(2)+x^(2))+(1)/(3)((2ax)/(a^(2)+x^(2)))^(3)+(1)/(5)((2ax)/(a^(2)+x^(2)))^(5)+.... =

If ax^2+2hxy+by^2=1 Find dy/dx