If for distribution `Sigma (x-5)=3,Sigma (x-5)^(2)=43` and total number of item is 18. Find the mean and standard deviation .

If for a distribution sum(x-5) = 3, sum(x - 5)^2 = 43 and the total number of item is 18, find the mean and standard deviation.

If for distribution sum(x-7)=3 , sum(x-7)^(2)=57 and total number of item is 20 . Find the mean and standard deviation.

If for a distribution, sum (x-5)=3, sum (x-5)^(2)=43 and total number of observations is 18, find the mean and standard deviation.

If for a distribution sum(x-5)=3,sum(x-5)^(2)=43 and the total number of terms is 18 then mean and variance are

If for a distribution sum(x-7)=6 and sum(x-7)^(2)=78 and the total number of items is 12 then mean and standard deviation are (i) barx=7.5,sigma=2.5 (ii) barx=7,sigma=2.5 (iii) barx=7.5,sigma=2 (iv) barx=7,sigma=2

If for distribution of 18 observations sum(x_(i)-5)=3 and sum(x_(i)-5)^(2)=43, find the mean and standard deviation.

If for distribution of 18 observations sum(x_i-5)=3a n dsum(x_i-5)^2=43 , find the mean and standard deviation.

If for distribution of 18 observations sum(x_i-5)=3a n dsum(x_i-5)^2=43 , find the mean and standard deviation.