An elevator starts from rest with a constant upward acceleration it moves 2m in the first `0.6` second. A passenger in the elevator is holding a 3 kg package by a vertical string When the elevator is moving What is the tension in the string?

An elevator starts from rest with a constant upward acceleration. It moves 5 m in the first 2 s. A passenger in the elevator is holding a 4 kg package by a vertical string. Find the tension in the string during the acceleration process in N.

A lift starts from rest with constant upward acceleration . It moves 1.5m in the first 0.4 secs. A person standing in the lift hold a packet of 2 kg by a string. Calculate the tension in the string during the motion.

A lift starts from rest with a constant upward acceleration It moves 1.5 m in the first 0.4 A person standing in the lift holds a packet of 2 kg by a string Calculate the tension in the string during the motion .

A lift starts from rest with a constant upward acceleration It moves 1.5 m in the first 0.4 A person standing in the lift holds a packet of 2 kg by a string Calculate the tension in the string during the motion .

An elevator starts from rest with a constant downward acceleration and covers 2.5m in first second If the lift weighs 200kg what would be the tension in the ropes of the lift ?

An elevator is accelerating upwards with a constant acceleration a ms^-2 . If a coin is dropped in it by a passenger, then.

An elevator is moving vertically up with a acceleration a the force exerted on the floor by a passenger of mass m is

An elevator is moving vertically up with a acceleration a the force exerted on the floor by a passenger of mass m is

A pendulum bob is hanging from the roof of an elevator with the help of a light string. When the elevator moves up with uniform acceleration 'a' the tension in the string is T_(1) . When the elevator moves down with the same acceleration, the tension in the string is T_(2) . If the elevator were stationary, the tension in the string would be