`100 ml` of water at `20^(@)C` and `100 ml` of water at `40^(@)C` are mixed in calorimeter until constant temperature reached. Now temperature of the mixture is `28^(@)C`. Water equivalent of calorimeter is

100ml of water at 20^@C and 100ml of water at 40^@C are mixed in calorimeter until constant temperature reached. Now temperature of the mixture is 28^@C . Water equivalent of calorimeter is

When 30 g water at 50^(@)C is poured into a calorimeter at a temperature 15^(@)C , the final temperature attained is 20^(@)C . What is the water equivalent of the calorimeter?

About 5g of water at 30^(@)C and 5g of ice at -20^(@)C are mixed together in a calorimeter. Calculate final temperature of the mixture. Water equivalent of the calorimeter is negligible. Specific heat of ice =0.5"cal"g^(-1)C^(@)-1) and latent heat of ice =80"cal"g^(-1)

When 0.400 kg of water at 30^(@)C is mixed with 0.150 kg of water at 25^(@)C contained in a calorimeter, the final temperature is found to be 27^(@)C , find the water equivalent of the calorimeter.

5 gm of steam at 100^(@)C is passed into calorimeter containing liquid. Temperature of liquid rises from 32^(@)C to 40^(@)C . Then water equivalent of calorimeter and contents is

5 g of water at 30^@C and 5 g of ice at -20^@C are mixed together in a calorimeter Find the final temperature of the mixure. Assume water equivalent of calorimeter to be negligible, sp. Heats of ice and water are 0.5 and 1 cal//g C^@ , and latent heat of ice is 80 cal//g

5 g of water at 30^@C and 5 g of ice at -20^@C are mixed together in a calorimeter Find the final temperature of the mixure. Assume water equivalent of calorimeter to be negligible, sp. Heats of ice and water are 0.5 and 1 cal//g C^@ , and latent heat of ice is 80 cal//g