According to Cauchy's formula, the refractive index `mu` of a material is related to wavelength `lamda` as………. .

Refractive index of a transparent material is :

How is the refractive index of a material related to the speed of light in it?

A beam of light of wavelength 400 nm is incident normally on a right angled prism as shown in Fig. It is observed that light just grazes along the surface AC after falling on it. If refractive index mu of the material of prism varies with wavelength lamda as mu = 1.2 + (b)/(lamda^2) Calculate the value of b and mu of prism material for lamda = 500 nm . Given theta = sin^-1 (0.625) . .

The refractive index of material varies with wavelength according to the Cauchy’s relation is

The angles of incidence and refraction of a monochromatic ray of light of wavelength lamda at an air-glass interface are i and r, respectively. A parallel beam of light with a small spread delta lamda in wavelength about a mean wavelength lamda is refracted at the same air-glass interface. The refractive index mu of glass depends on the wavelength lamda as mu(lamda) = a + b//lamda2 where a and b are constants. Then the angular spread in the angle of refraction of the beam is

The angles of incidence and refraction of a monochromatic ray of light of wavelength lamda at an air-glass interface are i and r, respectively. A parallel beam of light with a small spread delta lamda in wavelength about a mean wavelength lamda is refracted at the same air-glass interface. The refractive index mu of glass depends on the wavelength lamda as mu(lamda) = a + b//lamda2 where a and b are constants. Then the angular spread in the angle of refraction of the beam is

What is refraction of light? How is refractive index of material related to velocity of light?