Home
Class 9
MATHS
In a circle OD is perpendicular to chord...

In a circle OD is perpendicular to chord AB of a circle with centre O. If BC is a diameter then the AC/OD is:

Text Solution

Verified by Experts

We can draw the figure using given details.
Please refer to video for the diagram.
Now, in `Delta ABC and Delta DBO`
`/_BAC = /_BDO = 90^@`
`/_ABC = /_DBO` (Common angle)
So, by angle - angle similarity rule,
`Delta ABC ~ Delta DBO`
`:. (AC)/(BC) = (DO)/(BO)`
...
Promotional Banner

Similar Questions

Explore conceptually related problems

In the figure OD is perpendicular to the chord AB of a circle whose centre is O. If BC is a diameter, show that CA = 2OD

In the figure,OD is perpendicular to the chord AB of a circle whose centre is O .If BC is a diameter,show that CA=2OD

In the Figure,OD is perpendicular to the chord AB of a circle whose centre is O. If BC is a diameter,show that CA=2OD

In the Figure, O D is perpendicular to the chord A B of a circle whose centre is O . If B C is a diameter, show that C A=2 OD .

AD and AC are two equal chords of a circle with centre O. AB is the diameter of the circle. If angleCOD =140^@ , then angleOBC =

AB and CD are equal and parallel chords of a circle with centre O. Then AC passes through the centre O. [Agree // Disagree]

AB is a chord of a circle with centre O, AC is a diameter and AT is the tangent at A as shown in the figure. Prove that angleBAT=angleACB .

AB is a chord of a circle with centre O and diameter 20 cm. If AB = 12 cm, find the distance of AB from O.

In figure , AB and CD are two diameters of a circle ( with centre O) perpendicular to each other and OD is the diameter of the smaller circle . If OA = 7 cm , find the area of the shaded region.