[" In isosceles triangle whose are angle is "120^(@)" and "],[" radius of incircle is "sqrt(3)," then area of triangle is "]

Given an isosceles triangle, whose one angle is 120^(@) and radius of its in circle = sqrt(3) . Then the area of the triangle in square units is

Given an isosceles triangle,whose one angle is-2(pi)/(3) and the radius of its incircle =sqrt3 Then find the area of the triangle

One angle of an isosceles triangle is 120^0 and the radius of its incircle is sqrt(3)dot Then the area of the triangle in sq. units is (a) 7+12sqrt(3) (b) 12-7sqrt(3) (c) 12+7sqrt(3) (d) 4pi

One angle of an isosceles triangle is 120^0 and the radius of its incircle is sqrt(3)dot Then the area of the triangle in sq. units is (a) 7+12sqrt(3) (b) 12-7sqrt(3) (c) 12+7sqrt(3) (d) 4pi

One angle of an isosceles triangle is 120^0 and the radius of its incircle is sqrt(3)dot Then the area of the triangle in sq. units is (a) 7+12sqrt(3) (b) 12-7sqrt(3) (c) 12+7sqrt(3) (d) 4pi

One angle of an isosceles triangle is 120^(@) and the radius of its incricel is sqrt(3) .Then the area of the triangle in sq.units is 7+12sqrt(3)(b)12-7sqrt(3)12+7sqrt(3)(d)4 pi

One angle of an isosceles triangle is 120^0 and the radius of its incricle is sqrt(3)dot Then the area of the triangle in sq. units is (a) 7+12sqrt(3) " " (b) 12-7sqrt(3) 12+7sqrt(3) " " (d) 4pi

In an isosceles triangle ABC , angleA =120^@ ,a:b=