" 9.Evaluate "int_(0)^( pi/2)2sin x cos x tan^(-1)(sin x)dx

Evaluate: \int_{0}^((pi)/2)sin 2x tan^(-1)(sin x) dx

Evaluate int_(0)^(pi//2) (a sin x+b cos x)/(sin x+cos x)dx

Evaluate: int_(0)^((pi)/(2))|sin x-cos x|dx

Evaluate :int_(0)^((pi)/(2))(sin x+cos x)dx

int_(0)^( pi/2)(sin x-cos x)/(1+sin x*cos x)*dx

Evaluate: int_(0)^((pi)/(4))(sin x+cos x)/(9+16sin2x)dx

int_(0)^(pi//2)(sin x - cos x)/(1-sin x cos x)dx=

int_(0)^( pi/2)(sin x)/(1+cos x)dx

int_(0) ^(pi//2) ((sin x +cos x )^(2))/sqrt(1+ sin 2x)dx =

Prove that int_(0)^(a) f(x) dx = int_(0)^(a) f(a-x) dx . Hence, evaluate int_(0)^(pi//2) (sin x - cos x)/(1+ sin x cos x) dx.