| Two droplets of mercury with radius of 0.1cm and 0.2cm together form a large band, how much energy. Grow? For me the surface T = 435.5 x 10-3 N / m.

Two mercury droplets of radii 0.1 cm and 0.2 cm collapse into one single drop. What amount of energy is released? The surface tension of mercury T = 435. 5xx10^(-3) Nm^(-1)

Two mercury droplets of radii 0.1 cm and 0.2 cm collapse into one single drop. What amount of energy is released? The surface tension of mercury T = 435. 5xx10^(-3) Nm^(-1)

Two mercury droplets of radii 0.1 cm and 0.2 cm collapse into one single drop. What amount of energy is released ? The surface tension of mercury, T = 435.5 xx 10^-3 N m^-1

Two mercury droplets of radii 0.1 cm . And 0.2 cm . Collapse into one single drop .What amount of energy is released ? The surface tension of mercury T=435.5xx10^(-3)Nm^(-1)

Two mercury droplets of radii 0.2 cm and 0.4 cm collapse into one single drop. What amount of energy is released? The surface tension of mercury 440 xx 10^(-3) Nm^(-1) and g=10ms^(-2) .

A drop of mercury of radius 0.2 cm is broken into 8 droplets of the same size. Find the work done if the surface tension of mercury is 435.5 dyne/cm.

Two mercury droplets radii 0.1 cm and 0.2 cm collapse into one single drop. What amount of energy is released/absorbed? The sur4face tension of mercury T=435.5xx10^(-3)Nm^(-1)

Two droplets each radius r of mercury merge and form a bigger drop . If surface tension of mercury is T.Then what will be the surface energy ?

Eight droplets of mercury each of radius 1 mm coalesces into a single drop. Find the change in the surface energy. Surface tension of mercury is 0.465 J//m^2