" (vi) "1+i^(2)+i^(4)+i^(6)+i^(8)+...+i^(20)

1+i^(2)+i^(4)+i^(6)+... .+i^(2 n)=

1 + i^(2) + i^(4) + i^(6) = 0 .

Find the value of 1+i^(2)+i^(4)+i^(6)+i^(8)+...+i^(24)

Find the value of 1+i^(2)+i^(4)+i^(6)+i^(8)+...+i^(24)

The value of i^(2)+i^(4)+i^(6)+i^(8)... upto (2n+1) terms,where i^(2)=-1, is equal to:

1 + i^(2n) + i^(4n) + i^(6n)

If (i)^(2) = -1, (i)^(2) + (i)^(4) + (i)^(6) + ...... to (2n + 1) terms =

Write the following in the form x+iy: (i) (3+2i)(2-i) (ii) 2i^(2)+6i^(3)+3i^(16)-6i^(19)+4i^(25) . (iii) ((3-2i)(2+3i))/((1+2i)(2-i)) .